A model rocket is shot into the air off a building and its path is approximated by H(t) = -5(t + 2)(t - 6), where H is the height of the rocket above the ground in metres
and t is the elapsed time in seconds.
a. What is the height of the building?
b. When will the rocket hit the ground?
c. What is the maximum height of the rocket?
I
d. What is the height of the rocket at 3 seconds?
I

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step-by-step explanation:

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step-by-step explanation: 2

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)