Write a standard form equation for the line that contains a slope of 1/2, and passes through the point (-2, -3).

Sent a picture of the solution to the problem (s).

X^2 - 4x +(4/2^2) + y^2 + 8y + (8/2^2) = -4 + (4/2^2) + (8/2^2)(x + 2)^2 + (y + 4)^2 = -4 + 4 + 16your center is (-2, -4) and the radius is the sqrt of -4 + 4 + 16 which is 4

Graph a should be your answer