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Solve the problem by making up an equation. a man could arrive on time for an appointment if he drove the car at 40 mph; however, since he left the house 15 minutes late, he drove the car at 50 mph and arrive 3 minutes early for the appointment. how far from his house was his appointment?

Solve for b. ab + c= d b= a + old ob=allc-ch b= (d-c/a

On which number line are -3 and its opposite shown