How would you graph the solution set of the system of inequalities {3y≤2x+6} { 2x+y> 0}

1) Solve the first inequality

3y ≤ 2x + 6

=> y ≤ 2x/3 + 2

2) Draw the line y = 2x/3 + 2

3) Shade the region below the line y = 2x/3 + 2

4) Solve the inequality 2x + y > 0

=> y > - 2x

5) draw the line y = -2x

6) Shade the region above the line y = -2x

7) The solution is the region between the two lines shaded including the portion of the line y = 2x/3 + 2

Ithink if ur looking for a ratio it would be 12: 3