Atrain leaves los angeles at 2 p. m. heading north at 50 mph. if the next train leaves three hours later and also heads north at 60 mph, at what time will the second train catch up with the first?

The Second train will catch up with the first train after 15 hours which is 8a.m the following morning.

First train :

Departure time = 2 pm

Speed = 50 mph

Second train :

Departure time = 2 pm + 3 hours = 5 pm

Speed = 60 mph

Distance = speed × time

Distance already covered by first train before the departure of the second = 50 mph × 3 hpird = 150 miles

The number of hours needed for second train to catch up will be h;

(60 × h) = (50 × h) + 150

60h = 50h + 150

60h - 50h = 150

10h = 150

h = 150/ 10

h = 15

Second train will catch up after 15 hours :

Hence, time will be : (5pm + 15 hours) = 8 a.m the following morning.

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answer: 180

step-by-step explanation:

12-2=10

20-2=18

10x18=180

segment bisector

step-by-step explanation:

line segment bisector. definition: a line, ray or segment which cuts another line segment into two equal parts. try this drag one of the orange dots at a or b and note the the line ab always divides the line pq into two equal parts.

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