Given m with arrow = 3 î + 2 ĵ − 5 k and n with arrow = 6 î − 2 ĵ − 4 k, calculate the vector product m with arrow ✕ n with arrow.

We know that for two vectors u and v we have that the cross product is equal to : (u2v3 - u3v2) i + (u3v1 - u1v3) j + (u1v2 - u2v1) k Then we have that m x n : ( (2 *-4) - (-5 * -2) ) i + ( (-5*6) - (3 *-4) )j + ( ( 3*-2) - (2*6))k which becomes ( -8 - 10) i + ( -30 + 12) j + ( -6 - 12) k Thus the vector product of m and n is -18 i - 18j -18k