What is the measure of ∠spq in this rhombus?
m∠spr=(4x+11)°
m∠qpr=(5x−4)°
enter your answer in the box.

m∠SPQ=

Step-by-step explanation:

we know that

In a Rhombus the diagonals bisect the angles,

so

m∠SPR=m∠QPR

substitute the values

solve for x

m∠SPQ=m∠SPR+m∠QPR

m∠SPQ=

m∠SPQ=

m∠SPQ=

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation: