Three quadrilaterals exist such that ghjk ≅ asdf and ghjk ≅ vbnm. if mv measures 3 cm, which other segment must measure 3 cm? -a f -kj -fd -gj

FA= 3cm

Explanation:

Here, three quadrilaterals GHJK,ASDF  and GHJK are given such that,  

and

Therefore, (by transitive property of congruence)

And, if two shapes are congruent to each other then there corresponding sides and angles must be congruent.

That is, In quadrilaterals  ASDF and VBNM, edges AS, SD, DF and FA are corresponding to VB, BN, NM and MV respectively.

Therefore, FA=MV

But, MV= 3 cm ⇒FA=3cm.

Thus, Option (1) is correct.

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