Given: δabc, cm ⊥ ab ac = 10, cm = 4 am: bm = 2: 5 find: ab, cb

Step-by-step explanation:

 Given:  Δ ABC, CM⊥ AB

Now, consider  

Let In ΔCMA  H=- 10 , P= 4 , B= 2x

By, Pythagoras theorem,  

putting values we get,

⇒

⇒

⇒

which gives us and  

⇒

⇒

Now, Let In ΔCMB  H=- ? , P= 4 , B= 5√21

By, Pythagoras theorem,  

putting values we get,

⇒

⇒

⇒

⇒

Therefore,  

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step-by-step explanation:

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< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

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