What is the point-slope form of a line that has a slope of 5 and passes through the point (3, –4)? y – 3 = 5[x – (–4)] –4 – y1 = 5(3 – x1) y – (–4) = 3(x – 5) y – (–4) = 5(x – 3)

The generic form for this case is given by
 y = m (x-xo) + yo
 where
 xo: x coordinate
 me: y coordinate 
 Substituting the values we have
 y = 5 (x-3) - 4
 Therefore, the answer in this case is
 y – (–4) = 5(x – 3)