The question is shown in the picture but i will not mark brainliest if you show me a picture of what the graph should look like i need to know the exact two points to plot on the graph not a picture of the graph i already know what that looks like no pictures of graphs

(0,1) and (3,0) You've been given the equation y = (-1/3)x + 1, so finding points for the graph is quite simple. Let's do so: First, let's use an X value of 0 (I'm lazy and multiplying by 0 is rather simple). y = (-1/3)x + 1 y = (-1/3)*0 + 1 y = 0 + 1 y = 1 So one of the points is (0,1) Now let's see about doing another X value. Since the slope is -1/3 and I'm lazy I want to use an X value that is easy. And 3 would be a nice value since 3 on top and 3 on the bottom of a fraction cancel out. So let's use X = 3. y = (-1/3)x + 1 y = (-1/3)3 + 1 y = (-3/3) + 1 y = -1/1 + 1 y = -1 + 1 y = 0 And we have another point, which is (3,0) So two points on your line are (0,1) and (3,0).

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