Mathematics, 10.11.2019 19:31 lee9724
An archery target consists of five concentric circles. points for each region on the target are indicated. the radius of the bull’s-eye is 4.5”, and each ring surrounding it is 4.625” wide. round to the nearest hundredth.
a.) what is the area of the bull’s-eye?
b.) what is the area of the seven-point region?
c.) what is the area of the entire target?
d.)the probability of hitting the bull’s-eye on a random shot that hits the target is:
p(bull's eye)=area of bull's eye/area of target
e.)calculate the probability of hitting the bull’s-eye. express your answer as a percent. this gives the percentage of the time in which a shot that hits the target at random would be expected to hit the bull’s-eye.
Answers: 1
Mathematics, 21.06.2019 15:00
Idon’t understand this.. will someone ? will mark brainliest along with 20 points.
Answers: 1
Mathematics, 21.06.2019 16:30
Answer the following for 896.31 cm= km 100cm = 1m 1000m = 1km a) 0.0089631 b) 0.0089631 c) 8.9631 d) 89.631
Answers: 1
Mathematics, 21.06.2019 18:00
Given: and prove: what is the missing reason in the proof? given transitive property alternate interior angles theorem converse alternate interior angles theorem
Answers: 1
An archery target consists of five concentric circles. points for each region on the target are indi...
History, 04.11.2021 21:00
Social Studies, 04.11.2021 21:00
English, 04.11.2021 21:10
Mathematics, 04.11.2021 21:10
Business, 04.11.2021 21:10
Engineering, 04.11.2021 21:10
Mathematics, 04.11.2021 21:10
Computers and Technology, 04.11.2021 21:10
English, 04.11.2021 21:10