According to a certain country's department of education, 39.9% of 3-year-olds are enrolled in day care. what is the probability that a randomly selected 3-year-old is enrolled in day care?

The probability would be 39.9%

The given probability states that 39.9% of the 3 years olds are in daycare. Therefore, it would be obvious to assume that if you randomly selected a 3 year old, that would be the probability that he/she is in daycare.

(m+11n)^2=(m+11n)(m+11n)=m^2+11mn+11mn+121n^2=m^2+22mn×121n^2 for example; use foil: (a+b)(a+b)first. a^2outside. abinside. ablast. b^2