Put the following equation in slope intercept form: 3x - 2y = 14

Let the closed interval [a , b] be the domain of function f. the domain of f(x - 3) is given by (a) the open interval (a , b) (b) the closed interval [a , b] (c) the closed interval [a - 3 , b - 3] (d) the closed interval [a + 3 , b + 3]

Does the point (1, sqrt 7) lie on circle shown.

A(1,1) b(-3,0) c(-4,-1) d(3,-2) drag it to correct position