Akid jumping on a trampoline reaches a height of 0.925m. what was his speed when he left the trampoline?

As the kid rises to a height of 0.925 meters, his velocity decreases at the rate of 9.8 m/s each second. At the maximum height, his velocity is 0 m/s. Use the following equation to solve this problem.

vf^2 = vi^2 + 2 * a * d, vf = 0, a = -9.8
0 = vi^2 + 2 * -9.8 * 0.925
vi = √18.13
This is approximately 4.26 m/s.

I hope this helps, have a great day, and God bless.
Brainliest is always appreciated :)