Asprinter begins from rest and accelerates at the rate of 2 m/s^2 for .12 mi, what is the sprinters velocity?

v = 14.4 m/s

Explanation:

It is given that,

Initial speed of the sprinter, u = 0

Acceleration of the sprinter,

Time taken, t = 0.12 min = 7.2 s

Let v is the final speed of the sprinter. It can be calculated as :

v = u + at

v = 14.4 m/s

So, the sprinter's velocity is 14.4 m/s. Hence, this is the required solution.

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.