Acanoe is drifting left toward a hungry hippo with a velocity of 7\,\dfrac{\text{m}}{\text{s}}7 s m 7, space, start fraction, m, divided by, s, end fraction. the canoe rider starts paddling frantically, causing the canoe to travel to the right with a constant acceleration of 6 \,\dfrac{\text m}{{\text s}^2}6 s 2 m 6, space, start fraction, m, divided by, s, start superscript, 2, end superscript, end fraction. after 4\,\text s4s4, space, s, what is the velocity of the canoe?

17 m/s

Velocity and acceleration are vector quantities. Let leftwards be defines as negative and rightwards as positive direction.

It is given that canoe is drifting left with a velocity of

The canoe rider is moving towards right with a constant acceleration,

we need to find the velocity of canoe after 4 s.

we will use the equation of motion:

where, v is the final velocity, u is the initial velocity, a is the acceleration and t is the time.

Insert the values in the above equation:

Hence, velocity of canoe after 4 s would be 17 m/s.

explanation: magnetic pole, region at each end of a magnet where the external magnetic field is strongest. the south-seeking pole, or any pole similar to it, is called a south magnetic pole. unlike poles of different magnets attract each other; like poles repel each other.

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