Two men each weigh 650 n. one man carries +1.0 c of excess charge, the other −1.0 c of excess charge. how far apart must they be for their electric attraction to equal 650 n?

Coulomb's law:

F = k×q₁×q₂/r² where k ≈ 9.00×10⁹NC⁻²m²

Given values:

q₁ = +1.0C

q₂ = -1.0C

F = 650N

Substitute the terms in Coulomb's law with our given values. We will have to use the absolute value of q₂ to so the algebra works out. Solve for r:

650 = 9.00×10⁹×1.0×1.0/r²

r = 3721m

Taking significant figures into account:

what experimental evidence led scientists to change from the previous model to this one?

a few of the positive particles aimed at a gold foil seemed to bounce back.

the colors of light emitted from heated atoms had very specific energies.

experiments with water vapor showed that elements combine in specific proportions.

cathode rays were bent in the same way whenever a magnet was brought near them.

96.77 amp

explanation:

rl = 250/100 = 2.5 ohms.

egl = 250 + (100 × 0.1) + 2 = 262 v.

at 700 r.p.m., eg2 = 262 × 700/1000 = 183.4 v.

if ia is the new current, then eg2 - 2 - (ia × 0.1) = 2.5 ia

which means this will give ia = 96.77 amp.