The coordinate plane below shows the path of a bicyclist. each square represents 10 meters.

a. what is the displacement of the cyclist?

b. what is the distance traveled by the cyclist?

c. if the whole trip takes 45 seconds, what is the average speed of the cyclist?

d. if the whole trip takes 45 seconds, what is the average velocity of the cyclist?

e. between points b and c, the cyclist decreases hi speed from 4 m/s to 3 m/s in a time of 3 seconds. what is the magnitude of his acceleration?

Part A)

As we know see the graph

It travel from point A to G

so the displacement is from A to G directly

its 10 m towards North

Part B)

total distance we have to calculate total path length

so from A to B = 2 squares

from B to C = 4 squares

C to D = 1 square

D to E = 5 square

E to F = 1 square

F to G = 4 square

total distance = 2 + 4 + 1 + 5 + 1 + 4 = 17 square

1 square = 10 m

total distance = 170 m

PART C)

As we know that average speed is defined as

as we know that

total time = 45 s

total distance = 170 m

from above formula now

PART D)

As we know that average velocity is defined as

here we have

displacement = 10 m north

time = 45 s

now from above equation

Part E)

As we know that average acceleration is rate of change in the velocity

so here we have

final velocity = 3 m/s

initial velocity = 4 m/s

time = 3 s

now from the equation

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