One of the harmonics of a column of air in a tube that is open at one end and closed at the other has a frequency of 448 hz, and the next higher harmonic has a frequency of 576 hz. how long is the tube? the speed of sound in air is 343 m/s. one of the harmonics of a column of air in a tube that is open at one end and closed at the other has a frequency of 448 hz, and the next higher harmonic has a frequency of 576 hz. how long is the tube? the speed of sound in air is 343 m/s. 1.00 m 2.68 m 1.34 m 0.335 m 0.670 m

1.34 m

Explanation:

For an open-end tube, the frequency difference between two consecutive harmonics is equal to the fundamental frequency of the tube:

In this case, we have

so, the fundamental frequency is

For an open-end tube, the fundamental frequency is also given by:

where v is the speed of sound and L the length of the tube.

Since we know v = 343 m/s, we can solve the formula for L:

at positions a, g kinetic energy is maximum.

at position d, potential energy is maximum.

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