Asolid ball is at the top of a 2 m tall ramp. if it is given a push so that it’s initial speed is 1.75 m/s, what is it’s speed when it reaches the bottom of the ramp?

6.50m/s

Explanation:

Using conservation of energy, the total energy in the system is conserved. We know that the ball has potential energy initially because it is elevated 2 meters. We also know it has kinetic energy because it is given an initial speed of 1.75 m/s. At the bottom of the ramp, it loses all potential energy and is converted directly to kinetic energy. We can model the equation as below. U is the potential energy, K is the initial kinetic energy and K' is final kinetic energy.

Equation for kinetic energy is

and potential energy is:

Plug these equation to the first equation and simplify (v' is final speed):

Plug in the values:

Final speed is 6.50m/s

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