You have two steel solid spheres. sphere 2 has twice the radius of sphere 1. part a by what factor does the moment of inertia i2 of sphere 2 exceed the moment of inertia i1 of sphere 1?

moment of inertia of sphere 2 is 32 times the moment of inertia of sphere 1

Explanation:

The moment of inertia of a solid sphere about its axis is

where

M is the mass of the sphere

R is the radius of the sphere

The mass of the sphere can be rewritten as

where

is the density

is the volume of the sphere

So the moment of inertia becomes

Calling R the radius of sphere 1, the moment of inertia of sphere 1 is

where is the density of steel, since the sphere is made of steel

Sphere 2 has twice the radius of sphere 1, so

R' = 2R

and so its moment of inertia is

So, the moment of inertia of sphere 2 is 4 times the moment of inertia of sphere 1.

are there options? cause you ain’t. real specific

i am pretty sure it is c because when people are closer together, they cannot move as freely. picture being in a mostly full elevator, for instance. the people are right next to you, and you can barely move.