Initially, a particle is moving at 5.24 m/s at an angle of 35.2° above the horizontal. four seconds later, its velocity is 6.25 m/s at an angle of 57.5° below the horizontal. what was the particle's average acceleration during these 4.00 seconds in the x-direction (enter first) and the y-direction?

- 0.23

0.56

Explanation:

= initial velocity of the particle = =

= final velocity of the particle = =

t = time interval = 4.00 sec

= average acceleration = ?

Using the kinematics equation

= + t

= + (4)

= 4

=

hence

Average acceleration along x-direction = - 0.23

Average acceleration along y-direction = 0.56

answer: strength i guess

explanation:

pe = weightxheight = 2000x1000=2,000,000joules