An ideal spring is hung vertically from the ceiling. the spring constant is k = 125 n/m. a block of mass m = 650 g (1000 g = 1 kg) is then attached to the free end and block extends the spring under its weight until it stops moving. calculate the maximum extension of the spring due to the block. (hint: when the system comes to equilibrium, the net force on the block must be zer0.)

0.102 m

Explanation:

k = spring constant of the spring = 125 N/m

m = mass of the block attached to the spring = 650 g = 0.650 kg

x = maximum extension of the spring

h = height dropped by the block = x

Using conservation of energy

Spring potential energy gained = Gravitational potential energy lost

(0.5) k x² = mgh

(0.5) k x² = mgx

(0.5) (125) x = (0.650) (9.8)

x = 0.102 m

1= 26.17

2= 1.17

3=30.86

4=5.86

just took the assigment on edge

we need to know the time interval during which the force acts. impulse of force = momentum change