2. calculate the rate of heat loss per foot and the thermal resistance for a 6-in. schedule 40 steel pipe covered with a 3-in. thick layer of 85% magnesia. superheated steam at 300°f flows inside the pipe (hc = 30 btu/h ft2 °f) and still air at 60°f is on the outside (hc =5 btu/h ft2 °f).

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14

ok

explanation: