Ahydraulic jack has a small piston area a1 = 2 m^2 and the large piston area a2 = 20 m^2. a 1500 kg car needs to be lifted. a) how much force equivalent needed on the effort end f1? p1 = f1/a1, p1 = p2, (f = mass x g) b) what is the mechanical advantage of the system?

1471.5 Newton

10

Explanation:

Small piston area = A₁ = 2 m²

Large piston area A₂ = 20 m

m = Mass of car = 1500 kg

g = Acceleration due to gravity = 9.81 m/s²

Force

F = mg = 1500×9.81 = 14715 N

Force applied by car is 14715 N

a) Pascal's law

Force required is 1471.5 Newton

b) Mechanical advantage

Mechanical advantage is 10

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