An electron in a vacuum is first accelerated by a voltage of 71600 v and then enters a region in which there is a uniform magnetic field of 0.345 t at right angles to the direction of the electron's motion. the mass of the electron is 9.11 x 10-31 kg and its charge is 1.60218 x 10-19 c. what is the magnitude of the force on the electron due to the magnetic field? answer in units of n.

Explanation:

It is given that,

Potential difference,

Magnetic field,

The magnetic field is perpendicular to the direction of motion of electron i.e. the angle between velocity and magnetic filed is 90. We need to calculate the magnitude of the force on the electron due to the magnetic field.

Using the conservation of energy as :

Equation (1) becomes :

So, the force acting on the electron due to this magnetic field is . Hence, this is the required solution.

less than one you can't create energy

in order to follow the instructions and complete the statements, i need to use data from table c of your student guide. can you think of a way to let me see your student guide for a while ? i can't answer the question without the data in table c.