Acopper rod is 0.875 m long with a rectangular cross section of dimensions 0.0515 m by 0.0855 m. the ends of the rod are held at 42.9°c and 97.7°c, but the rod is otherwise insulated from its environment. find the heat current (the amount of heat that flows per unit time) through the rod. the thermal conductivity of copper is 385 w/(m⋅k) . heat current:

heat flow is 106.1 W

Explanation:

given data

length = 0.875 m

dimensions x = 0.0515 m

dimensions y = 0.0855 m

temperature = 42.9°C and 97.7°C

thermal conductivity K = 385 W/(m⋅K)

to find out

heat flows

solution

we will apply here formula for heat flow that is

heat flow = K × Δt × A / L    ..........................1

so here Δt = 97.7°C - 42.9°C = 54.8°C

and area A = xy = 0.0515 × 0.0855 = 4.40 × m²

so put all value in equation 1 we get heat flow

heat flow = K × Δt × A / L

heat flow = 385 × 54.8 × 4.40 ×  / 0.875

heat flow = 106.1

so here heat flow is 106.1 W

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