The acceleration due to gravity on mars is twice that on the moon. if you hit a baseball on the moon with the same effort (and therefore same speed and angle) as on mars, how far yet wered rked out ofwould the ball would travel on the moon compared to on mars? neglect air resistance on mars. flag estion select one: a. twice as far as on mars b. four times as far as on mars c. the same distance as on mars d, half as far as on mars

option (d)

Explanation:

Acceleration due to gravity on mars = twice the acceleration due to gravity on moon

According to the conservation of energy, the kinetic energy at the time of hitting is totally converted into potential energy at height.

On the surface of moon, let the value of acceleration due to gravity is a and the ball rises upto height h.

So, kinetic energy = Potential energy

1/2 mv^2 = m x a x h     (1)

On the surface of mars, the value of acceleration due to gravity is 2a and the ball rises upto height h'.

So, kinetic energy = Potential energy

1/2 mv^2 = m x 2a x h'     (2)

By equating equation (1) and equation (2),we get

2h' = h

h' = h / 2

Thus, the ball rises upto half of the height as that of moon.

i already answered it by 34/s

= initial pressure

= final pressure = 2

= initial volume

= final volume = /4

= initial temperature = 20 c = 20 + 273 = 293 k

= final temperature = ?

using the equation