A5.86 kg block initially at rest is pulled to the right along a horizontal surface by a constant, horizontal force of 14.4 n. the coefficient of kinetic friction is 0.14. the acceleration of gravity is 9.8 m/s 2 . find the speed of the block after it has moved 4.98 m. answer in units of m/s.

3.3m/s

Explanation:

1. Find the acceleration a:

Given: normal force: N, the horizontal force: F, friction coefficient: μ, mass: m, acceleration of gravity: g. The sum of all forces in the horizontal plane is:

∑F = ma = F - μN = F - μmg

Solve for the acceleration a:

(i) a = F/m - μg

2. Use the equations of motion to calculate the velocity v for a uniform acceleration a, time t and initial velocity v₀:

(ii) v = at + v₀

position x, initial position x₀:

(iii) x = 0.5at² + v₀t + x₀

Eliminate time t by plugging in eq. (ii) into eq. (iii) with v₀ = 0 and x₀ = 0:

(iv) x = 0.5v²/a

Solve for v:

(v) v = √(2xa) = √(2*x*( F/m - μg)) = √(2*4.89 * (14.4/5.86 - 0.14*9.8))

answer: the direction of the wind is expressed as the direction from which the wind is blowing. for example, easterly winds blow from east to west, while westerly winds blow from west to east.

explanation:

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

according to question, we have said that if the population has twice its initial population, then it becomes

so, time taken to reach this above mentioned population is given by

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.