Physics, 09.09.2019 16:10 makaileep1623

Agolf ball is hit from ground level at an angle of 3030 degrees above ground level. the terrain is level. the ball lands 55.231255.2312 meters away. what was the initial speed of the golf ball?

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Answer from: 19brendaddavenport

The initial speed of the golf ball was 25 m/s.

Explanation:

To find the initial speed of a projectile motion we must first find the motion equation corresponding to each axis:

For X axis we have an Uniform Rectilinear Motion, since no forces act along it:

$x_{(t)}=v_{ix}.t+x_i$ , where $v_{ix}$ stands for the initial speed component on x axis, and x_i is the initial position on x axis (zero, in this case).

For Y axis we have a Constant Acceleration Motion, since the gravitational force acts along it:

$y_{(t)}=-\frac{1}{2} g.t^{2} +v_{iy}.t+y_i$ , where g is the acceleration of gravity, $v_{iy}$ stands for the initial speed component on y axis, and y_i is the initial position on y axis (zero, in this case).

We can describe the initial speed's components as follow:

$v_{ix}=v_i.cos(30^0)$ and $v_{iy}=v_i.sin(30^0)$

Keeping this in mind, we're just three steps away from the answer.

The first step is expressing t in terms of x:

$t=\frac{x}{v_i.cos(30^0)}$

The second step is replacing this expression for t on the y axis equation:

$y_{(x)}=-\frac{1}{2} .g.(\frac{x}{v_i.cos(30^0)} )^2+\frac{v_i}{v_i} \frac{sin(30^0)}{cos(30^0)} .x$

Finally, we use the fact that when x=55.2312 m the golf ball lands, it means y=0 m, and resolve the equation for v_i

$0m=-\frac{1}{2} .9,8\frac{m}{s^2}.(\frac{55,2312m}{v_i.cos(30^0)} )^2+\frac{sin(30^0)}{cos(30^0)} .55,2312m$

Obtaining

$v_i=25\frac{m}{s}$

Answer from: frankgore7836

25 m/s

Explanation:

Angle of projection, θ = 30°

Horizontal distance, r = 55.231 m

Let u be the velocity of projection.

Use the formula of horizontal range

$R=\frac{u^{2}Sin2\theta }{g}$

By substituting the values, we get

$55.231=\frac{u^{2}Sin60 }{9.8}$

$55.231=\frac{u^{2}\times 0.866 }{9.8}$

u = 25 m/s

thus, the initial velocity of golf ball is 25 m/s.

Answer from: Quest

total distance travelled = 60 miles

total time taken =1.5 hours

average speed = total distance / total time

60 / 1.5

= 40

therefore, average speed = 40 m/h

happy to

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Answer from: Quest

Answer: it will take 4.36 seconds to reach her average velocity 10.69 miles/hour.explanation: we have equation of motion $s=ut+\frac{1}{2} at^2$ ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/s $s=0*t+\frac{1}{2} *2.18*t^2$ $s=1.09t^2[/ 2equating equation 1 and 2 [tex]4.75t = 1.09t^2\\ \\ t=4.36 seconds.$ so it will take 4.36 seconds to reach her average velocity 10.69 miles/hour.

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Agolf ball is hit from ground level at an angle of 3030 degrees above ground level. the terrain is l...

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