Aball is thrown with velocity of 10 m/s upwards. if the ball is caught 1 m above its initial position, what is the speed of the ball when it is caught?

v = 8.96 m/s

Explanation:

Initial speed of the ball, u = 10 m/s

It caught 1 meter above its initial position.

Acceleration due to gravity,

We need to find the final speed of the ball when it is caught. Let is equal to v. To find the value of v, use third equation of motion as :

v = 8.96 m/s

So, the speed of the ball when it is caught is 8.96 m/s. Hence, this is the required solution.

the temperature and the pressure affect solubility. temperature affects by changing the properties of the solvent. the increase in pressure increases solubility, the decrease in pressure decreases solubility.