The car starts from rest and accelerates with an acceleration of 2 m/s^2 for 5 s. it then travels at a constant speed for 20 s, before decelerating at -5 m/s^2 until it reaches zero speed. how much distance did the car cover during this journey.

Total distance covered during the journey is 235 m

Solution:

As per the question:

Initial velocity, v = 0 m/s

Acceleration, a =

Time, t = 5 s

Now,

For this, we use eqn 2 of motion:

The final speed of car after t = 5 s is given by:

v' = v + at

v' = 0 + 2(5) = 10 m/s

Now, the car travels at constant speed of 10 m/s for t' = 20 s with a = 0:

d' = 200 m

Now, the car accelerates at a= - 5 until its final speed, v" = 0 m/s:

d" = 10 m

Total distance covered = d + d' + d"  = 25 + 200 + 10 = 235 m

c

explanation:

i believe the answer is c and this is only worth 10 points you might wanna change it

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