Abicyclist is finishing his repair of a flat tire when a friend rides by with a constant speed of 3.1 m/s . two seconds later the bicyclist hops on his bike and accelerates at 2.4 m/s^2 until he catches his friend. a) how much time does it take until he catches his friend (after his friend passes him)?
express your answer using two significant figures.

5.91 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

Distance = Speed × Time

⇒Distance = 3.1t

Distance traveled by bicycle that passes through = 3.1t

They both travel the same distance

Hence, time taken by the bicyclist to catch the other bicyclist is 5.91 seconds

frequency or wavelenth of em radiation in a vacuum

massxgravity x heght=weightxheight= pe

4900=490xh

h=10