What is the amount of heat, in sl units, necessary to melt 1 lb of ice?

Heat required to melt 1 lb of ice is 151.469 KJ

Explanation:

We have given mass of ice = 1 lb

We know that 1 lb = 0.4535 kg

Latent heat of fusion for ice =334 KJ/kg

Amount if heat for fusion of ice is given by

, here m is mass of ice and L is latent heat of fusion

So heat

So heat required to melt 1 lb of ice is equal to 151.469 KJ

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find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2