If an electron is accelerated from rest through a potential difference of 9.9 kv, what is its resulting speed? (e = 1.60 × 10-19 c, k = 1/4πε0 = 8.99 × 109 n · m2/c2, m el = 9.11 x 10-31 kg) if an electron is accelerated from rest through a potential difference of 9.9 kv, what is its resulting speed? ( = 1.60 × 10-19 c, = 1/4π = 8.99 × 109 n · m2/c2, el = 9.11 x 10-31 kg) 4.9 × 107 m/s 3.9 × 107 m/s 2.9 × 107 m/s 5.9 × 107 m/s

So speed of electron will be

Explanation:

We have given potential difference V = 9.9 KV

Charge on electron

So energy of electron

This energy of electron will be equal to kinetic energy of electron

So

So speed of electron will be

in order to follow the instructions and complete the statements, i need to use data from table c of your student guide. can you think of a way to let me see your student guide for a while ? i can't answer the question without the data in table c.