Your friend of mass 80 kg can just barely float in freshwater. calculate her approximate volume.
express your answer to two significant figures and include the appropriate units.

0.080 m³

Explanation:

According to Archimedes' principle:

The weight of the fluid dispersed by the object is equal to the weight of the object which is floating on the fluid.

Thus, the mass of the friend = 80 kg

The mass of water displaced = 80 kg

Also, The density of fresh water =1000 kg/m³

Volume = mass/density.

So volume of the water displaced = 80 kg /1000 kg/m³ = 0.08 m³.

Thus, the volume of the friend is also equal to this volume = 0.080 m³  ( answer to two significant figures)

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