Suppose that after a number of measurements, you were to find an average time δt=(0.0031±0.0002) s using a gate separation δd=(1.0±.1) cm when dropping a ball from the height h=(0.510±0.002) m. calculate g. give your answer in units of m/s2 to three digits (even though they may not all end up being i dont know what a gate seperation is. when i use a=(2h)/(t^2) to calculate g i get 106555.6712 and thats way too big. how do i work the gate seperation into it to get g i know how to do the uncertainty part.

Distance covered = speed x timethe distance traveled going against the stream = distance traveled with the stream.therefore it is the speed and the time that are the variables.as he travels the same distance both ways, speed x time is the same for each way.going upstream his speed is 4 kph; going downstream his speed is 6 kph.therefore we have two simultaneous equations: time upstream x 4 = time downstream x 6time upstream + time downstream = 60 minutestherefore we have the equation: time upstream = 6/10 hour, time downstream therefore = 4/10 hour.distance traveled at 4km/hr in 6/10 hour = 24/10 = 2.4km.check: distance traveled at 6km/hr in 4/10 hour = 24/10 = 2.4km.

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The answer is a hat a nice day sir or ma'am