Two airplanes leave an airport at the same
time. the velocity of the first airplane is
750 m/h at a heading of 51.3
◦
. the velocity
of the second is 620 m/h at a heading of 163◦
.
how far apart are they after 2.4 h?
answer in units of m.

The airplanes are 2726.68m apart.

Why?

To calculate how far are the planes apart, we need to find the angle between their displacements, then, we can use the law of cosines to solve the problem.

Now that we know the angle, we can use the law of cosines to find the distance between the two airplanes:

Also, we need to remember the formula to calculate distance:

Substituting we have:

Hence, we have that the airplanes are 2726.68m apart.

Have a nice day!

the current is 0.6

voltage ÷ resistance = current

so 12 ÷ 20 = 0.6

molecules are free to separate from each other and will take on the shape of the container. molecules move completely at random and high speeds. they vibrate in a fixed position and do not move around much. molecules expand to the edge of their container.