Salmon often jump waterfalls to reach their breeding grounds. starting downstream, 1.84 m away from a waterfall 0.251 m in height, at what minimum speed must a salmon jumping at an angle of 38.3 ◦ leave the water to continue upstream? the acceleration due to gravity is 9.81 m/s 2 .

4.73 m/s

Explanation:

R=1.84  m

H=0.251 m

∅=38.3°

For Horizontal Motion

aₓ=0      uₓ=ucos∅

x=uₓt+

R=ucos∅*t+0

1.84=ucos(38.3)*t

t=

For Vertical Motion

Y=Uy*t+

By putting value

0.251=usin∅()-()

0.251=sin(38.3)()-()

0.251=1.452-

u²=22.41

u=4.73 m/s

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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