You kick a ball with a speed of 4 m/s at an angle of 10ﾟ. how far away does the ball land?

The ball goes 0.555 meter  far away when kicked with a speed of 4 m/s at an angle of 10ﾟ.

Explanation :

From the given statements, we know  

Initial Velocity (u) = 4 m/s

Angle at which it is projected (θ) = 10 degree

Let acceleration due to gravity (g) = 9.8 m/

Range = ?

Using the formula of Range, and substituting the values

Range=  

            =

                = = 0.555 m

the answer is to check all of them! they all apply well at least i think so!

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s