A50.0 n box is at rest on a horizontal surface. the coefficient of static friction between the box and the
surface is 0.50, and the coefficient of kinetic friction is 0.30. a horizontal 20.0 n force is then exerted
on the box. the magnitude of the acceleration of the box is most nearly

Acceleration will be

Explanation:

We have given that a 50 N box is at rest

Coefficient of static friction = 0.5

And coefficient of kinetic friction = 0.3

Force exerted on the box = 20 N

Static friction force =

As the static friction force is greater than the force exerted force so box will not move and so acceleration will be

momentum of soft ball three times less than baskey ball

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