An elevator and its load have a combined mass of 2000 kg. find the tension in the supporting cable when the elevator, originally moving downward at 12 m/s, is brought to rest with constant acceleration in a distance of 26 m.3

14060 N

Explanation:

We start by calculating the acceleration of the elevator. This can be found using the suvat equation:

where

v = 0 is the final velocity

u = 12 m/s is the initial velocity

a is the acceleration

s = 26 m is the stopping distance

Solving for a, we find

Now let's write the equation of the forces acting on the elevator. Taking upward as positive direction:

where

T is the tension in the cable

(mg) is the weight of the elevator, where

m = 2000 kg is the mass

is the acceleration of gravity

is the deceleration

Solving for T,

measuring things 1 litre of water

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.