Aspecimen of aluminum having a rectangular cross section 9.5 mm × 13.0 mm (0.3740 in. × 0.5118 in.) is pulled in tension with 35600 n (8003 lbf) force, producing only elastic deformation. the elastic modulus for aluminum is 69 gpa (or 10 × 106 psi). calculate the resulting strain.

〖4.1x10〗^(-3)

Explanation:

From the question, the parameters given are:

We can solve this using the formula for elastic modulus ( E ) = stress/strain  

making strain the subject of the formula the equation above becomes strain= stress/ elastic modulus

Where strain= change in length/ length

And  

Stress= force/ area

now let’s calculate value for stress

Stress= 35600/0.0001235=288,259,109  N/m^2

substituting the value for stress into the equation strain= stress/ elastic modulus we have

Strain= 288,259,109 / 69 x 〖10〗^9 = 〖4.1x10〗^(-3)

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