Acrate of 45.2-kg tools rests on a horizontal floor. you exert a gradually increasing horizontal push on it and observe that the crate just begins to move when your force exceeds 310n . after that you must reduce your push to 231n to keep it moving at a steady 25.2cm/s .

part a: what is the coefficient of static friction between the crate and the floor?

part b: what is the coefficient of kinetic friction between the crate and the floor?

part c: what push must you exert to give it an acceleration of 1.13m/s^2 ? (in n)

part d: suppose you were performing the same experiment on this crate but were doing it on the moon instead, where the acceleration due to gravity is 1.62 m/s^2. what magnitude push would cause it to move? (in n)

part e: what would its acceleration be if you maintained the push in part c?

best answer

Explanation:

A )

A force of 310 N initiates motion in mass 45.2 kg so

Coefficient of static friction = force / normal reaction

= force / weight

= 310 / ( 45.2 x 9.8 )

=  0 .7

B )

A force of 231  N maintains  uniform motion in mass 45.2 kg so

Coefficient of kinetic  friction = force / normal reaction

= force / weight

= 231  / ( 45.2 x 9.8 )

=  0.52

C )

In motion,  friction force acting = 231 N .

If F be the required force

F - 231 = 45.2 x 1.13 ( net force = mass x acceleration )

= 282.07 N

D )

On moon g = 1.62

Force of static friction there

= weight x coefficient of friction

= 45.2 x 1.62 x .7

= 51.25  N

Magnitude of push required = 51.25 N .

the answer is to check all of them! they all apply well at least i think so!

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s