Abullet we shot through two cardboard discs, which have a distance of 80 cm from each other. these two cardboard discs rotate on a shaft with a circulation time of 6.67 x 10-4 min. what speed does the bullet have when both bullet points are shifted by 12 ° from each other?

Explanation:

Assume that the bullet is shot at a velocity of (v m/s) and it will take t time to pass the second plate.

by the definition of then angular velocity (ω)

ω=\frac{angular displacement}{time }[/tex]

Lets find the time to turn the next plate by 12 degrees , using θ=ωt

]t=\frac{12}{8995.5} =1.334*10^{-3}[/tex]

the bullet has to travel 80cm in this much of time to make a hole in the second plate. We can find the speed using this equation

(we have to convert cm into meters first)

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the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.