Atennis ball is tossed upward with a speed of 3.0\,\dfrac{\text m}{\text s}3.0 s m 3, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction. we can ignore air resistance. what is the velocity of the ball 0.40\,\text s0.40s0, point, 40, start text, s, end text after the toss?

The velocity of the ball is 0.92 m/s in the downward direction (-0.92 m/s).

Explanation:

Hi there!

The equation for the velocity of an object thrown upward is the following:

v = v0 + g · t

Where:

v = velocity of the ball.

v0 = initial velocity.

g = acceleration due to gravity (-9.8 m/s² considering the upward direction as positive).

t = time.

To find the velocity of the ball at t = 0.40 s, we have to replace "t" by 0.40 s in the equation:

v = v0 + g · t

v = 3.0 m/s - 9.8 m/s² · 0.40 s

v = -0.92 m/s

The velocity of the ball is 0.92 m/s in the downward direction (-0.92 m/s).

6/12=1/2

step-by-step explanation:

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explanation:

there is no change in the electric potential energy as it is in rest on both conditions.