Abaseball pitcher throws the ball in a motion where there is rotation of the forearm about the elbow joint as well as other movements. if the linear velocity of the ball relative to the elbow joint is m/s at a distance of m from the joint and the moment of inertia of the forearm is kg·m2, what is the rotational kinetic energy of the forearm?

K = ½ kg m2 / s2

Explanation:

The kinetic energy rotation is given by the expression

    K = ½ I w²

Where I is the moment of inertia and w is the angular velocity.

We have a relationship between linear and angular velocity

    v = w r  

Where r  the distance from the point of rotation, in this case it is the point or where the ball is, so the linear velocity is the same as the ball.

      w = v / r

We replace

      K = ½ I (v / r)²

Let's calculate

      K = ½ kg m2 )(m/s )/ m) 2

      K = ½ kg m2 / s2

the answer is a. the yacht traveled from the dock north to the 200-meter marker in the bay in less than 5 minutes, giving the passengers several more hours to fish.

im doing peak rn so sry if its wrong

another example of kinetic energy would be,

kinetic energy   >     moving energy

answer   >   letter choice (c),   a hammer falling off a table.

hope that !                                         : )