A5000-pf capacitor is charged to 100 v and then quickly connected to an 80-mh inductor.

determine

(a) the maximum energy stored in the magnetic field of the inductor,

(b) the peak value of the current, and

(c) the frequency of oscillation of the circuit.

a)U= 25 x 10⁻⁶ J

b)I = 25 m A

c)f= 7957.74 Hz

Explanation:

Given that

C= 5000 pF

V= 100 V

L= 80 m H

The maximum charge on the capacitor Q = C V

Q= 5000 x 10⁻¹² x 100 C

Q= 5 x 10⁻⁷ C

The frequency ω  given as

ω = 50000 rad/s

The frequency in Hz

ω = 2π f

50000=  2π f

f= 7957.74 Hz

The maximum  current given as

I = Q ω

I=  5 x 10⁻⁷  x  50000

I = 25 m A

The maximum stored energy in the inductor U

U= 25 x 10⁻⁶ J

your answer is c! hope this : )