Imagine another solar system, with a star of the same mass as the sun. suppose a planet with a mass twice that of earth (2 earth) orbits at a distance of 1 au from the star. what is the orbital period of this planet?

Time period, T = 403.78 years

Explanation:

It is given that,

Orbital distance,

Mass of the Earth,

Mass of the planet,

Let T is the orbital period of this planet. The Kepler's third law of motion gives the relation between the orbital period and the orbital distance.

or

T = 403.78 years

So, the orbital period of this planet is 404 years. Hence, this is the required solution.

total distance travelled = 60 miles

total time taken =1.5 hours

average speed = total distance / total time

60 / 1.5

= 40

therefore, average speed = 40 m/h

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